Auto calculating map dimensions

Auto calculating map dimensions

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Mon Nov 8 21:34:59 2021   by   Mizuki
Currently there's a couple of different map projections with different "optimal" width:height ratio, 2:1 for most, 1:1 for orthographic, 2.117:1 for icosahedral etc
Manually specifying widths and heights requires you to remember which projection you are using and scale the ratio accordingly.
I propose having a way to semi-automate calculating the map dimensions to satisfy the respective projections, ie if you specify only a mapheight of 1000, the program should automatically calculate the width based on the projection you chose, 2000 for most, 1000 for orthographic, 2117 for icosahedral etc, and vice versa if you only specify widths
 
Tue Nov 9 10:10:16 2021   by   Torben
That is only relevant for full-planet maps, but it might be a good idea to do so anyway.  I'll look into it.
 
Wed May 11 23:47:38 2022   by   Ron Vantreese
I'm also interested.

For the 2:1 maps, I am thinking that the exact calculation is:
Dimensions(f(x)) = (2x, x + 1)
The +1 accounts for the equator.
 
Thu May 12 01:20:00 2022   by   Ron Vantreese
I'm also interested.

For the 2:1 maps, I am thinking that the exact calculation is:
Dimensions(f(x)) = (2x, x + 1)
The +1 accounts for the equator.
 

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