| Sat Nov 17 01:44:49 2018 by vxi |
| I'm getting a parse error on line 4, but I see nothing wrong with it. I'm sorry if it's obvious. Thank you for any help you can provide a:=d8; w:=d20; t:=0; if a = w then t:=2; else t:=0; if a > w then t:=1; else t:=0; if a = {4,6,8} & w = {2,4,6} then t:=t+1; else t:=0; if a = {3,5,7} & w = {1,3,5} then t:=t+1; else t:=0; if t = 2 then 1 else 0 |
| Sun Nov 18 01:45:05 2018 by wyrdR |
| if a = w then t:=2; else t:=0; if a > w then t:=1; else t:=0; if a = {4,6,8} & w = {2,4,6} then t:=t+1; else t:=0; if a = {3,5,7} & w = {1,3,5} then t:=t+1; else t:=0; should be t:=if a = w then 2 else 0; t=:if a > w then 1 else 0; t:=if a = {4,6,8} & w = {2,4,6} then t+1 else 0; t:=if a = {3,5,7} & w = {1,3,5} then t+1 else 0; |
| Sun Nov 18 02:03:04 2018 by wyrdR |
| There's still issues, and I made a mistake. I'm testing a few things out... Be back soon. |
| Sun Nov 18 02:32:27 2018 by wyrdR |
a:=d8; w:=d20; t:=0; t:= if a > w then 1 else 0; \ if a is larger t = 1 t:= if a = w then 2 else t; \ if equal to = 2 t:=if a = {4,6,8} & w = {2,4,6} then t+1 else t; t:=if a = {3,5,7} & w = {1,3,5} then t+1 else t; t |
| Mon Nov 19 05:51:38 2018 by vxi |
| Thank you! This format makes perfect sense. |