| Fri May 11 18:28:12 2018 by Ciarlatano |
| Hello! I'm looking for help, I'm trying to write a program to calculate the probability of this: roll Nd6, count the number of dice that show a 5+. If it rolls 6 (or sometimes 5 and 6) counts 2 successes instead of 1. I can't seem to wrap my head around the problem :( |
| Sat May 12 15:05:56 2018 by Torben |
The simplest way to let 5s count as 1 and 6s count as 2 is to use the choose operator:sum N#choose{0,0,0,0,1,2} |
| Sat May 12 18:39:10 2018 by Ciarlatano |
| I'll try to write something following your advice! Thank you very much |