| Tue Apr 22 22:55:25 2014 by Daniel |
| Hi Torben, I want to sum 3d8, but only if have no duplicate...if have 2 or 3 equals I want a reroll until have only different. I try this but doesnt work: [code] repeat x:=d8 y:=d8 w:=d8 until (count different {x,y,w}) = 3 sum {x,y,w} [/code] do you know a way to do this? Thanks. |
| Wed Apr 23 09:55:31 2014 by Torben |
You can do it this way:sum repeat x := 3d6 until (count different x) = 3The reason your variant does not work is that you can have only one assignment between repeat and until. |
| Wed Apr 23 15:52:43 2014 by Daniel |
| Whell, I tried to simplify my problem but I confuse more... I need x,y and w because at realy I donīt sum all of them in the end...I will compare x and y, them compare the with w. There any way to reroll 3 dices until have no pares, and them get x,y,w to make my comparations? Thanks. |
| Thu Apr 24 09:33:44 2014 by Torben |
One way you could do it is to reroll the three dice as a group (like in my previous reply) and then randomly select which of the three is x, y and w. You can do that this way:xyw := repeat a := 3d6 until (count different a) = 3;Statistically, this gives the same result as if you pick which dice are x, y and z beforehand and then reroll all until they are different. |
| Thu Apr 24 15:09:56 2014 by Daniel |
| Thanks Torben, By the way, I want to know if I may mention you and the Troll in the acknowledgment of my book that will be released in 2 or 3 years. Is an indie RPG and Troll was critical for the dice mechanic development. |
| Fri Apr 25 10:22:44 2014 by Torben |
| A mention would be nice, thank you, (but not required). |